document.write( "Question 481073: In 1990, the life expectancy of males in a certain country was 70.2 years. In 1997, it was 72.7 years...?\r
\n" ); document.write( "\n" ); document.write( "Let E represent the life expectancy in year t and let t represent the number of years since 1990.\r
\n" ); document.write( "\n" ); document.write( " The linear function E(t) that fits the data is
\n" ); document.write( " E(t)=__t + ___. (round to the nearest tenth)
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\n" ); document.write( "Use the function to predict the life expenctancy of males in 2008.
\n" ); document.write( " E(13)=___. (round to the nearest tenth
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Algebra.Com's Answer #329467 by mananth(16946)\"\" \"About 
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year
\n" ); document.write( "1990 70.2 years
\n" ); document.write( "1997 72.7 years
\n" ); document.write( "Difference
\n" ); document.write( "7 2.5
\n" ); document.write( "Increase in life expectancy per year = 2.5 / 7 = 0.36
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\n" ); document.write( "E(t)= 70.2 + 0.357 t
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\n" ); document.write( "2008 t= 18
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\n" ); document.write( "E(t)= 70.2 + 0.357 * 18
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\n" ); document.write( "In 2008 --K (18)= 76.63 years \r
\n" ); document.write( "\n" ); document.write( "K ( 13 )= 74.84 years\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
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