document.write( "Question 481073: In 1990, the life expectancy of males in a certain country was 70.2 years. In 1997, it was 72.7 years...?\r
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document.write( "Let E represent the life expectancy in year t and let t represent the number of years since 1990.\r
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document.write( " The linear function E(t) that fits the data is
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document.write( " E(t)=__t + ___. (round to the nearest tenth)
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document.write( "Use the function to predict the life expenctancy of males in 2008.
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document.write( " E(13)=___. (round to the nearest tenth \n" );
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Algebra.Com's Answer #329467 by mananth(16946)![]() ![]() You can put this solution on YOUR website! year \n" ); document.write( "1990 70.2 years \n" ); document.write( "1997 72.7 years \n" ); document.write( "Difference \n" ); document.write( "7 2.5 \n" ); document.write( "Increase in life expectancy per year = 2.5 / 7 = 0.36 \n" ); document.write( " \n" ); document.write( "E(t)= 70.2 + 0.357 t \n" ); document.write( " \n" ); document.write( "2008 t= 18 \n" ); document.write( " \n" ); document.write( "E(t)= 70.2 + 0.357 * 18 \n" ); document.write( " \n" ); document.write( "In 2008 --K (18)= 76.63 years \r \n" ); document.write( "\n" ); document.write( "K ( 13 )= 74.84 years\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |