document.write( "Question 481126: Good day tutors of algebra.com\r
\n" ); document.write( "\n" ); document.write( "I dunno if I posted to the right category but here goes\r
\n" ); document.write( "\n" ); document.write( "Jack starts walking at 4kph . After a time , he hitches a ride with an old truck that travels 30kph . In 10 hours of walking and riding , he covers 157km . How long did he walk and how long did he ride? \r
\n" ); document.write( "\n" ); document.write( "I'm so confuse with this question because the distance was combined \r
\n" ); document.write( "\n" ); document.write( "thanks in advance \n" ); document.write( "
Algebra.Com's Answer #329463 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let him walk x km
\n" ); document.write( "so he trucked 157-x km\r
\n" ); document.write( "\n" ); document.write( "time walked = x/4
\n" ); document.write( "time trucked = (157-x)/30\r
\n" ); document.write( "\n" ); document.write( "Total time = 10 hours\r
\n" ); document.write( "\n" ); document.write( "x/4 + (157-x)/30 =10\r
\n" ); document.write( "\n" ); document.write( "LCD = 60\r
\n" ); document.write( "\n" ); document.write( "multiply the equation by LCD
\n" ); document.write( "15x+(157-x)*2 = 600
\n" ); document.write( "15x+314-2x=600
\n" ); document.write( "13x=600-314
\n" ); document.write( "13x=286
\n" ); document.write( "x=22 the distance walked
\n" ); document.write( "speed walked = 4 kph
\n" ); document.write( "time walked = 22/4 = 5.5 hours\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
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