document.write( "Question 481084: \"5 years ago mother was 7 times as old as her daughter. 5 years hence she will be 3 times as old as her daughter. find their present age?\" \n" ); document.write( "
Algebra.Com's Answer #329447 by Aswathy(23)![]() ![]() ![]() You can put this solution on YOUR website! Let daughter's and mother's present ages be x and y respectively. \n" ); document.write( "As,5 years ago mother's age was 7 times her daughter's age, so,mother's will be y-5=7(x-5) \n" ); document.write( "Similarly,5 years from now the mother's age will be y+5=3(x+5) \n" ); document.write( "By solving both the equations we get x=10 & y=40. \n" ); document.write( "So the present ages of mother and her daughter are 40 & 10 years respectively. \n" ); document.write( " |