document.write( "Question 481056: Hi could you please solve- 16+ 12x- x^3 when x=3
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Algebra.Com's Answer #329435 by nerdybill(7384) You can put this solution on YOUR website! 16+ 12x- x^3 when x=3 \n" ); document.write( ". \n" ); document.write( "just substitute the x with a 3 and solve: \n" ); document.write( "16+ 12(3)- 3^3 \n" ); document.write( "16+ 36 - 27 \n" ); document.write( "16+ 36 - 27 \n" ); document.write( "52 - 27 \n" ); document.write( "25 \n" ); document.write( " |