document.write( "Question 481081: \"5 years ago mother was 7 times as old as her doughter. 5 years hence she will be 3 times as old as her doughter. find their present age?\" \n" ); document.write( "
Algebra.Com's Answer #329427 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! m-5=7(d-5) \n" ); document.write( "m+5=3(d+5) \n" ); document.write( "------------- \n" ); document.write( "m-5=7d-35 \n" ); document.write( "m=7d-30 \n" ); document.write( "7d-30+5=3d+15 \n" ); document.write( "7d-25=3d+15 \n" ); document.write( "4d=40 \n" ); document.write( "d=10 \n" ); document.write( "m=40 \n" ); document.write( "The mother is 40; the daughter is 10..\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |