document.write( "Question 481082: In a recent study 90 percent of the homes in the United States were found to have color TVs. In a sample of nine homes, what is the probability that:
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document.write( "a. All nine have color TVs?
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document.write( "b. Less than five have color TVs?
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document.write( "c. More than five have color TVs?
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document.write( "d. At least seven homes have color TVs?\r
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document.write( "I am confused I was told this problem is Binomial but I can't seem to solve it can someone please help me out please. Thank you very much. \n" );
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Algebra.Com's Answer #329426 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In a recent study 90 percent of the homes in the United States were found to have color TVs. In a sample of nine homes, what is the probability that: \n" ); document.write( "---- \n" ); document.write( "Binomial Problem with n = 9 and p = 0.9 \n" ); document.write( "---- \n" ); document.write( "a. All nine have color TVs? \n" ); document.write( "P(x=9) = 9C9(0.9)^9*(0.1)^0 = 0.9^9 = 0.3874 \n" ); document.write( "---------------------------------------------------- \n" ); document.write( "b. Less than five have color TVs? \n" ); document.write( "P(0<= x <=4) = binomcdf(9,0.9,4) = 0.0008909 \n" ); document.write( "----------------------------------------- \n" ); document.write( "c. More than five have color TVs? \n" ); document.write( "P(6<= x <=9) = 1 - binomcdf(9,0.9,5) = 0.9917 \n" ); document.write( "----------------------------------------- \n" ); document.write( "d. At least seven homes have color TVs? \n" ); document.write( "P(7<= x <=9) = 1-binomcdf(9,0.9,6) = 0.9470 \n" ); document.write( "================================== \n" ); document.write( "I used a TI-84 to get the cumulative probabilities. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |