document.write( "Question 480922: Find the normal approximation for the binomial probability that x = 6, where n = 15 and p = 0.3. Compare this probability to the value of P(x=6) \r
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Algebra.Com's Answer #329403 by stanbon(75887)\"\" \"About 
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Find the normal approximation for the binomial probability that x = 6,
\n" ); document.write( "where n = 15 and p = 0.3. Compare this probability to the value of P(x=6)
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\n" ); document.write( "u = np = 15*0.3 = 4.5
\n" ); document.write( "s = sqrt(4.5*0.7) = 1.7748
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\n" ); document.write( "P(x = 6) = P(5.5 < x < 6.5)
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\n" ); document.write( "z(5.5) = (5.5-4.5)/1.7748 = 0.5634
\n" ); document.write( "z(6.5) = (6.5-4.5)/1.7748 = 1.1269
\n" ); document.write( "---------------
\n" ); document.write( "P(5.5 < x < 6.5) = P(0.5634< z <1.1269) = 0.1567
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\n" ); document.write( "Using the binomial distribution:
\n" ); document.write( "P(x = 5) = binompdf(15,0.3,5) = 0.2061
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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