document.write( "Question 481040: You are given the sample mean and the sample standard deviation. Use this information to sonstruct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.\r
\n" );
document.write( "\n" );
document.write( "A random sample of 40 eight- ounce servings of different juice drinks has a mean of 99.1 calories and a
\n" );
document.write( "Atandard deviation of 48.5 calories.
\n" );
document.write( "The 90% confidence interval is (__,__). (round to one decimal place as needed.)
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #329400 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! You are given the sample mean and the sample standard deviation. Use this information to sonstruct the 90% and 95% confidence intervals for the population mean. \n" ); document.write( "---- \n" ); document.write( "More confidence requires a wider interval. \n" ); document.write( "The 95CI is wider \n" ); document.write( " Which interval is wider? If convenient, use technology to construct the confidence intervals. \n" ); document.write( "------------------------------------- \n" ); document.write( " \n" ); document.write( "A random sample of 40 eight- ounce servings of different juice drinks has a mean of 99.1 calories and a standard deviation of 48.5 calories. \n" ); document.write( "The 90% confidence interval is (83.589,114.61). (round to one decimal place as needed.) \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |