document.write( "Question 49623: Hi! How do you factor completely: 6x^2-5y-3xy+10x. I would show you work but I forgot how to do this kind of problem. Could you please tell me how to solve it using a couple different methods? Thanks!\r
\n" ); document.write( "\n" ); document.write( "*anonymous* \n" ); document.write( "

Algebra.Com's Answer #32938 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
There's no need to be shy here, \"anonymous\"\r
\n" ); document.write( "\n" ); document.write( "Factor completely:
\n" ); document.write( " $\"6x%5E2-5y-3xy%2B10x\"$ You can factor by \"grouping\". Look for terms that have commom factors and group them with parentheses.
\n" ); document.write( " $\"%286x%5E2%2B10x%29-%283xy%2B5y%29\"$ From the first parentheses, factor out 2x and from the second parentheses, factor out a y.
\n" ); document.write( " $\"%282x%283x%2B5%29%29-y%283x%2B5%29\"$ Now, from this you can factor out the (3x+5)
\n" ); document.write( " $\"%283x%2B5%29%282x-y%29\"$ ...and you're done! \n" ); document.write( "

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