document.write( "Question 481023: What is logx+log(x-1)=log2? Solve for x \n" ); document.write( "

Algebra.Com's Answer #329376 by stanbon(75887) $\"\"$ $\"About$

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logx+log(x-1)=log2
\n" ); document.write( "------------------------
\n" ); document.write( "log[x(x-1)] = log(2)
\n" ); document.write( "----
\n" ); document.write( "x(x-1) = 2
\n" ); document.write( "x^2-x-2 = 0
\n" ); document.write( "----
\n" ); document.write( "Factor:
\n" ); document.write( "(x-2)(x+1) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 2
\n" ); document.write( "=================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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