document.write( "Question 480952: A manufacturer of window frames knows from long experience that 5 percent of the production will have some type of minor defect that will require and adjustment. What is the probability that in a sample of 20 window frames:
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document.write( " a. None will need adjustment?
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document.write( " b. At least one will need adjustment?
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document.write( " c. More than two will need adjustment?\r
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document.write( "I know this is binomial but I am still having trouble solving the problem. Could some please help me and Thank you very much. \n" );
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Algebra.Com's Answer #329354 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A manufacturer of window frames knows from long experience that 5 percent of the production will have some type of minor defect that will require and adjustment. What is the probability that in a sample of 20 window frames: \n" ); document.write( "a. None will need adjustment? \n" ); document.write( "P(x = 0) = 20C0(0.05)^0*0.95^20 = 0.95^20 = 0.3585 \n" ); document.write( "-------------------- \n" ); document.write( "b. At least one will need adjustment? \n" ); document.write( "P(1<= x <=20) = 1 - P(x = 0) = 1-3585 = 0.6415 \n" ); document.write( "-------------------- \n" ); document.write( "c. More than two will need adjustment? \n" ); document.write( "P(3<= x <=20) = 1 - P(0<=x <=2) = 0.0755 \n" ); document.write( "========= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========= \n" ); document.write( " \n" ); document.write( " |