document.write( "Question 480953: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 60 miles per hour. Train A passes a station at 3:10 A.M. If train B passes the same station at 3:22 A.M, at what time will train B catch up to train A?? \n" ); document.write( "
Algebra.Com's Answer #329330 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 60 miles per hour. Train A passes a station at 3:10 A.M. If train B passes the same station at 3:22 A.M, at what time will train B catch up to train A? \n" ); document.write( "** \n" ); document.write( "From the station, Train B must make up the 12 minutes he is behind Train A to catch up with Train A. \n" ); document.write( "Both trains cover the same distance: \n" ); document.write( "let x=distance both trains will have traveled when Train B catches up with Train A. \n" ); document.write( "Travel time=distance/speed \n" ); document.write( "Travel time of Train A-Travel time of Train B=12 minutes=12/60 hr \n" ); document.write( "x/40-x/60=12/60 \n" ); document.write( "multiply by LCD:120 \n" ); document.write( "3x-2x=24 \n" ); document.write( "x=24 miles \n" ); document.write( "Travel time of train B =24/60=2/5 hrs=24 min \n" ); document.write( "ans: \n" ); document.write( "Train B catches up with Train A at 3.22+24 min=3.46 A.M. \n" ); document.write( " |