document.write( "Question 480912: Alex is 6 years older than Frank. The sum of their ages is 50. Find Alex's age and Frank's age. \n" ); document.write( "
Algebra.Com's Answer #329311 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Alex’s age=A
\n" ); document.write( "Frank’s age=F\r
\n" ); document.write( "\n" ); document.write( "Now Alex is 6 years older than Frank, Which means if we substract 6 from Alex’s age both Alex and Frank will be of same age:
\n" ); document.write( "A-6=F..............(1)
\n" ); document.write( "Alex’s age and Frank’s age sum is equal to 50
\n" ); document.write( "A+F=50..........(2)\r
\n" ); document.write( "\n" ); document.write( "Now put the value of F from (1) into (2)
\n" ); document.write( "A+(A-6)=50
\n" ); document.write( "A+A-6=50
\n" ); document.write( "2A-6=50
\n" ); document.write( "Add 6 both sides of the above equation.
\n" ); document.write( "2A-6+6=50+6
\n" ); document.write( "2A=56
\n" ); document.write( "Divide by 2 both sides of the above equation
\n" ); document.write( "2A/2=56/2
\n" ); document.write( "A=28
\n" ); document.write( "So Alex is 28 years old.\r
\n" ); document.write( "\n" ); document.write( "Now put Alex’s age in equation (1)
\n" ); document.write( "A-6=F
\n" ); document.write( "28-6=F
\n" ); document.write( "22=F
\n" ); document.write( "F=22
\n" ); document.write( "So Frank is 22 years old. \n" ); document.write( "
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