document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480806>Question 480806</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve triangle ABC<BR>\n" );
document.write( "given: angle A is 69 degrees, side b is 34, and side c is 46 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329294 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329294\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve triangle ABC<BR>\n" );
document.write( "given: angle A is 69 degrees, side b is 34, and side c is 46<BR>\n" );
document.write( "=========================================================<BR>\n" );
document.write( "We can first solve for a using the law of cosines:<BR>\n" );
document.write( "a^2 = b^2 + c^2 - 2bc*cos(A)<BR>\n" );
document.write( "a^2 = 34^2 + 46^2 - 2*34*46*cos(69)<BR>\n" );
document.write( "This gives a = 46.379<BR>\n" );
document.write( "Now we can use the law of sines to solve for the other two angles:<BR>\n" );
document.write( "sin(69)/46.379 = sin(B)/34<BR>\n" );
document.write( "Solving for B gives B = 43.188<BR>\n" );
document.write( "Since the sum of the 3 angles is 180 deg, the angle C is:<BR>\n" );
document.write( "C = 180 - 69 - 43.188 = 67.812<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );