document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480849>Question 480849</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has twice the area of a square.  The length of the rectangle is 12 cm greater and the width is 8 cm greater than a side of a square . Find the perimeter of the square </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329256 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329256\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> side of square = x<BR>\n" );
document.write( "Are of square = x^2\r<BR>\n" );
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document.write( "Rectangle length = (x+12)<BR>\n" );
document.write( "rectangle width = (x+8)<BR>\n" );
document.write( "Area of rectangle = (x+12)(x+8)\r<BR>\n" );
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document.write( "(x+12)(x+8) =2x^2\r<BR>\n" );
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document.write( "x^2+20x+96=2x^2<BR>\n" );
document.write( "x^2-20x-96=0<BR>\n" );
document.write( "x^2-24x+4x-96=0<BR>\n" );
document.write( "x(x-24)+4(x-24)=0<BR>\n" );
document.write( "(x-24)(x+4)=0<BR>\n" );
document.write( "ignore negative<BR>\n" );
document.write( "x= 24 the side of square <BR>\n" );
document.write( "Perimeter of square = 24 *4 = 96cm\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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