document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480826>Question 480826</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a triangle has a base B and the altitude of the triangle is twice the base, then the area of the triangle is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329244 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area of a triangle is equal to (Base * Height)/2<BR>\n" );
document.write( "let B = base<BR>\n" );
document.write( "let H = height<BR>\n" );
document.write( "formula becomes A = (B*H)/2<BR>\n" );
document.write( "you are given that:<BR>\n" );
document.write( "H = 2B<BR>\n" );
document.write( "formula becomes A = (B*2*B)/2<BR>\n" );
document.write( "this can be rewritten as A = (2*B^2)/2<BR>\n" );
document.write( "the 2 in the numerator and denominator cancel out and you get:<BR>\n" );
document.write( "A = B^2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );