document.write( "Question 480799: a man had a bag of sweets he gave one to his son and 1/7 of the remaining and what he was left he gave to his daughter two sweet and 1/7 of the remaining sweets.the two children found that they have same number of sweets how many sweets are there in original bag \n" ); document.write( "
Algebra.Com's Answer #329221 by mathstutor494(120)\"\" \"About 
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Let there be \"x\" sweets in original bag\r
\n" ); document.write( "\n" ); document.write( "Gave 1 to son so remaining are x-1 sweets
\n" ); document.write( "1/7 of remaining sweets = (x-1)*(1/7)=> (x-1)/7
\n" ); document.write( "
\n" ); document.write( "Hence total sweets given to son
\n" ); document.write( "1+((x-1)/7)
\n" ); document.write( "(x+6)/7 ...............................(1)\r
\n" ); document.write( "\n" ); document.write( "Sweets remaining in the bag after giving to son
\n" ); document.write( "x-((x+6)/7)
\n" ); document.write( "(6x-6)/7\r
\n" ); document.write( "\n" ); document.write( "Out of this he gave 2 sweets to daughter so remaining sweets are
\n" ); document.write( "((6x-6)/7)-2
\n" ); document.write( "=(6x-20)/7\r
\n" ); document.write( "\n" ); document.write( "Further, he gave 1/7 from remaining lot to his daughter...
\n" ); document.write( "((6x-20)/7)*(1/7)
\n" ); document.write( "=(6x-20)/49\r
\n" ); document.write( "\n" ); document.write( "So total sweets with daughter
\n" ); document.write( "((6x-20)/49)+2
\n" ); document.write( "=(6x+78)/49 ..............................(2)\r
\n" ); document.write( "\n" ); document.write( "Since the problem specifies that the two children found that they have same number of sweets, so expressions (1) and (2) are equal.
\n" ); document.write( "Accordingly\r
\n" ); document.write( "\n" ); document.write( "(x+6)/7 = (6x+78)/49 \r
\n" ); document.write( "\n" ); document.write( "Solving for x gives value of 36\r
\n" ); document.write( "\n" ); document.write( "Ans : 36 sweets there in original bag\r
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