document.write( "Question 480762: f(x)=x^2+1 find for f(x+2)
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document.write( "f(x+2)=(x+2)^2 +1
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document.write( " =x^2+4+1
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document.write( " =x^2 +5\r
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document.write( "But book answer is: f(x+2)=x^2+4x=5
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document.write( "I can not figure out where you get the 4x- what step am I missing? \n" );
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Algebra.Com's Answer #329216 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! You have to apply FOIL \n" ); document.write( ". \n" ); document.write( "f(x)=x^2+1 find for f(x+2) \n" ); document.write( ". \n" ); document.write( "f(x+2)=(x+2)^2+1 \n" ); document.write( "f(x+2)=(x+2)(x+2)+1 \n" ); document.write( "f(x+2)=(x^2+2x+2x+4)+1 \n" ); document.write( "f(x+2)=(x^2+4x+4)+1 \n" ); document.write( "f(x+2)= x^2+4x+5 \n" ); document.write( " \n" ); document.write( " |