document.write( "Question 480790: x^2+y=18
\n" ); document.write( "-3x-y=0
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Algebra.Com's Answer #329200 by mananth(16946)\"\" \"About 
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x^2+y=18
\n" ); document.write( "y= 18-x^2\r
\n" ); document.write( "\n" ); document.write( "-3x-y=0
\n" ); document.write( "substitute y in the second equation
\n" ); document.write( "-3x-(18-x^2)=0
\n" ); document.write( "-3x-18x+x^2=0\r
\n" ); document.write( "\n" ); document.write( "x^2-3x-18=0
\n" ); document.write( "x^2-6x+3x-18=0
\n" ); document.write( "x(x-6)-3(x-6)=0
\n" ); document.write( "(x-6)(x-3) =0\r
\n" ); document.write( "\n" ); document.write( "x= 6 OR 3
\n" ); document.write( "when x=6, y=-18. (6,-18)
\n" ); document.write( "when x=3,y=9. (3,9)
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