document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480763>Question 480763</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Car A leaves the cafe traveling at 40 mph. Car B leaves the cafe 4 hours later, and travels at 60 mph. If they are both headed in the same direction, how far from the cafe will they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329199 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Car A	40	kmph						<BR>\n" );
document.write( "Car B	60	kmph						<BR>\n" );
document.write( "Car A		08:00						<BR>\n" );
document.write( "Car B		12:00						<BR>\n" );
document.write( "Difference in time=		04:00	=>	4	hours			<BR>\n" );
document.write( "Car A	will have covered	160	miles	before 	Car B		starts	from home<BR>\n" );
document.write( "catch up distance=		160	miles					<BR>\n" );
document.write( "catch up speed =		60	-40	mph				<BR>\n" );
document.write( "catch up speed =		20	mph					<BR>\n" );
document.write( "Catchup time = catchup distance/catch up speed								<BR>\n" );
document.write( "catch up time=		160	/	20				<BR>\n" );
document.write( "catch up time=		8	hours					\r<BR>\n" );
document.write( "\n" );
document.write( "In 8 hours Car B would travel 8*60 = 480 miles.<BR>\n" );
document.write( "That is where they meet\r<BR>\n" );
document.write( "\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );