document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480751>Question 480751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Forty parcent of the fuel was consumed. If 1215gallons of fuel remain, how much fuel was present initially?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329184 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 40% was consumed, then the 1215 left over is 60% of the original amount.\r<BR>\n" );
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document.write( "Find out what number 1215 is 60% of:\r<BR>\n" );
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document.write( "The formula a = pb works for any percent problem you encounter:<BR>\n" );
document.write( "a is the \"part\", p is the \"percent\" (as a decimal), b is the \"whole\"\r<BR>\n" );
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document.write( "1215 = .6b {substituted given information into formula, changing 60% to .6}<BR>\n" );
document.write( "b = 2,025 {divided both sides by .6}\r<BR>\n" );
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document.write( "2,025 gallons is the original amount<BR>\n" );
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