document.write( "Question 480714: Instructions say: \"Find an equation in standard form for the line described.\" The question is: \"Through P (5, -2) and perpendicular to the line 2x-3y=6. Please help!!! \n" ); document.write( "
Algebra.Com's Answer #329177 by lwsshak3(11628)\"\" \"About 
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\"Find an equation in standard form for the line described.\" The question is: \"Through P (5, -2) and perpendicular to the line 2x-3y=6.
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\n" ); document.write( "Standard form of equation for a straight line:
\n" ); document.write( "y=mx+b, m=slope and b=y-intercept
\n" ); document.write( "..
\n" ); document.write( "rewrite given equation
\n" ); document.write( "2x-3y=6
\n" ); document.write( "3y=2x-6
\n" ); document.write( "slope=2
\n" ); document.write( "..
\n" ); document.write( "Perpendicular line:
\n" ); document.write( "slope=negative reciprocal of slope of given equation=-1/2
\n" ); document.write( "equation: y=(-1/2)x+b
\n" ); document.write( "solving for b using coordinates of given point (5, -2) thru which line passes.
\n" ); document.write( "-2=-5/2+b
\n" ); document.write( "b=-2+5/2=-4/2+5/2=1/2
\n" ); document.write( "Equation: y=x/2+1/2
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