document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480662>Question 480662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi i'm having a little trouble with a section in my math packet for the summer. I already had help on a similar problem but im still having trouble. I have to determine the domain and range for y = sqrt2x-1. Thanks for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329158 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329158\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> determine the domain and range for y = sqrt(2x-1)<BR>\n" );
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document.write( "Domain = ?<BR>\n" );
document.write( "The radicand (2x-1) cannot be negative.<BR>\n" );
document.write( "Solve 2x-1 >= 0<BR>\n" );
document.write( "2x >= 1<BR>\n" );
document.write( "x >= 1/2<BR>\n" );
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document.write( "Domain: All Real Numbers greater than or equal to 1/2.<BR>\n" );
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document.write( "Range = ?<BR>\n" );
document.write( "The sqrt cannot be negative:<BR>\n" );
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document.write( "Range: All Real Numbers greater than or equal to 0.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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