document.write( "Question 480621: I also need help solving this literal equations. I need to solve for x.
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document.write( "cx + 4c = 5x + 7c \n" );
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Algebra.Com's Answer #329152 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " We only want x terms on the left, \r\n" ); document.write( " cx + 4c = 5x + 7c so get the x term off the right\r\n" ); document.write( " -5x -5x by adding -5x to both sides.\r\n" ); document.write( " ------------------------\r\n" ); document.write( " -5x + cx + 4c = 7c 4c does not contain x, so \r\n" ); document.write( " - 4c - 4c get if off the left side by\r\n" ); document.write( " ------------------------ adding -4c to both sides.\r\n" ); document.write( " -5x + cx = 3c \r\n" ); document.write( " Factor out x on the left\r\n" ); document.write( " x(-5 + c) = 3c\r\n" ); document.write( " Get rid of the multiplied -5+c\r\n" ); document.write( " by dividing both sides by it\r\n" ); document.write( " x(-5 + c) 3c\r\n" ); document.write( " 覧覧覧覧覧 = 覧覧覧覧覧\r\n" ); document.write( " -5 + c -5 + c \r\n" ); document.write( " \r\n" ); document.write( " Cancel the -5+c on the left:\r\n" ); document.write( "\r\n" ); document.write( " 3c\r\n" ); document.write( " x = 覧覧覧覧覧\r\n" ); document.write( " -5 + c \r\n" ); document.write( "\r\n" ); document.write( "That's the answer, but maybe your teacher would think it would look better\r\n" ); document.write( "if you wrote the denominator like this:\r\n" ); document.write( "\r\n" ); document.write( " 3c\r\n" ); document.write( " x = 覧覧覧覧覧\r\n" ); document.write( " c - 5 \r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |