document.write( "Question 480647: The sum of the digits of a two-digit number is 13. When the digits are reversed, the new number is 27 more than the original number. What is the original number?\r
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Algebra.Com's Answer #329145 by emargo19(101)\"\" \"About 
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Let one be n
\n" ); document.write( "Let tens=t\r
\n" ); document.write( "\n" ); document.write( "\"t%2Bn=13\" ----eq1
\n" ); document.write( "\"10n%2Bt=27%2B10t%2Bn\" -----eq2\r
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\n" ); document.write( "\n" ); document.write( "Lets sorts the terms in eq2
\n" ); document.write( "\"t-10t-n%2B10n=27\"
\n" ); document.write( "\"-9t%2B9n=27\"\r
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\n" ); document.write( "\n" ); document.write( "multiply eq1 by (9)
\n" ); document.write( "\"9t%2B9n=117\"
\n" ); document.write( "\"-9t%2B9n=27\"
\n" ); document.write( "---------------
\n" ); document.write( " \"18n=144\"
\n" ); document.write( " \"n=8\"\r
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\n" ); document.write( "\n" ); document.write( "substitute n=8 in eq1
\n" ); document.write( "So,
\n" ); document.write( "\"t%2B8=13\"
\n" ); document.write( "\"t=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=5\" and \"n=8\"
\n" ); document.write( "The original number is \"5%2A10%2B8=50%2B8=58\"\r
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