document.write( "Question 49573: factor completely
\n" ); document.write( "3(x-2)^2-3(x-2)-6 \n" ); document.write( "

Algebra.Com's Answer #32913 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Factor completely:
\n" ); document.write( " $\"3%28x-2%29%5E2+-+3%28x-2%29+-+6\"$
\n" ); document.write( "You can factor this expression in a couple of ways.\r
\n" ); document.write( "\n" ); document.write( "1) $\"3%28x-2%29%5E2-3%28x-2%29-6\"$ Factor a 3.
\n" ); document.write( " $\"3%28%28x-2%29%5E2-%28x-2%29-2%29\"$ Expand the parentheses.
\n" ); document.write( " $\"3%28%28x%5E2-4x%2B4%29-%28x-2%29-2%29\"$ Simplify.
\n" ); document.write( " $\"3%28x%5E2-5x%2B4%29\"$ Finally, factor the parentheses.
\n" ); document.write( " $\"3%28x-1%29%28x-4%29\"$ \r
\n" ); document.write( "\n" ); document.write( "The other way:
\n" ); document.write( "2) $\"3%28x-2%29%5E2-3%28x-2%29-6\"$ Again, factor the 3.
\n" ); document.write( " $\"3%28%28x-2%29%5E2-%28x-2%29-2%29\"$ Now substitute a for (x-2).
\n" ); document.write( " $\"3%28a%5E2-a-2%29\"$ Factor the parentheses.
\n" ); document.write( " $\"3%28a-2%29%28a%2B1%29\"$ Now replace a with (x-2).
\n" ); document.write( " $\"3%28x-2-2%29%28x-2%2B1%29\"$ Simplify this.
\n" ); document.write( " $\"3%28x-4%29%28x-1%29\"$ Compare this answer with $\"3%28x-1%29%28x-4%29\"$ above! \n" ); document.write( "

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