document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480585>Question 480585</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I determine the height of the laser beam 30 ft away from the face of the building if the equation is y=-(2/3)x+30?\r<BR>\n" );
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document.write( "Please show the graph work so that I may compare.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329126 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329126\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I determine the height of the laser beam 30 ft away from the face of the building if the equation is y=-(2/3)x+30?\r<BR>\n" );
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document.write( "Please show the graph work so that I may compare. <BR>\n" );
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document.write( "The distance from the face of the building = x<BR>\n" );
document.write( "The height of the beam = y<BR>\n" );
document.write( "Therefore, solve for y when x = 30<BR>\n" );
document.write( "y = (-2/3)*30 + 30 = 10<BR>\n" );
document.write( "So the height is 10 ft.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-10%2C35%2C-10%2C40%2Cy=-2x%2F3%2B30%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-10%2C35%2C-10%2C40%2Cy=-2x%2F3%2B30%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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