document.write( "Question 480446: a picture has a height that is 4/3 its width.it is to be enlarged to have an area of 192 square inches. what will be the dimensions of the enlargement? \n" ); document.write( "
Algebra.Com's Answer #329120 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a picture has a height that is 4/3 its width.it is to be enlarged to have an area of 192 square inches. what will be the dimensions of the enlargement? \n" ); document.write( ": \n" ); document.write( "The relationship between the width and height should remain the same after the enlargement: \n" ); document.write( ": \n" ); document.write( "Let w = the enlarged width \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "w* \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "4w^2 = 3(192 \n" ); document.write( "4w^2 = 576 \n" ); document.write( "w^2 = \n" ); document.write( "w^2 = 144 \n" ); document.write( "w = \n" ); document.write( "w = 12 in is the width \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |