document.write( "Question 480446: a picture has a height that is 4/3 its width.it is to be enlarged to have an area of 192 square inches. what will be the dimensions of the enlargement? \n" ); document.write( "
Algebra.Com's Answer #329120 by ankor@dixie-net.com(22740)\"\" \"About 
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a picture has a height that is 4/3 its width.it is to be enlarged to have an area of 192 square inches. what will be the dimensions of the enlargement?
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\n" ); document.write( "The relationship between the width and height should remain the same after the enlargement:
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\n" ); document.write( "Let w = the enlarged width
\n" ); document.write( "then
\n" ); document.write( "\"4%2F3\"w = the enlarged height
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\n" ); document.write( "w*\"4%2F3\"w = 192
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\n" ); document.write( "\"4%2F3\"w^2 = 192
\n" ); document.write( "4w^2 = 3(192
\n" ); document.write( "4w^2 = 576
\n" ); document.write( "w^2 = \"576%2F4\"
\n" ); document.write( "w^2 = 144
\n" ); document.write( "w = \"sqrt%28144%29\"
\n" ); document.write( "w = 12 in is the width
\n" ); document.write( "then
\n" ); document.write( "\"4%2F3\"*12 = 16 in is the height\r
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