document.write( "Question 480564: Can you please help me with this problem? I need to solve for x. \r
\n" ); document.write( "\n" ); document.write( " 6x-2 / 3 + x-3 / 2 = 1/5
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Algebra.Com's Answer #329100 by Maths68(1474)\"\" \"About 
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6x-2 / 3 + x-3 / 2 = 1/5
\n" ); document.write( "Taking LCM 3 and 2 which is 6 so multiply by 6 both sides
\n" ); document.write( "6(6x-2 / 3) + 6(x-3 / 2) =6(1/5)
\n" ); document.write( "2(6x-2) + 3(x-3) = 6/5
\n" ); document.write( "12x-4+3x-9=6/5
\n" ); document.write( "15x-13=6/5
\n" ); document.write( "Add 13 both sides of the equation
\n" ); document.write( "15x-13+13=6/5+13
\n" ); document.write( "15x=(6+65)/5
\n" ); document.write( "15x=71/5
\n" ); document.write( "Divide by 15 both sides
\n" ); document.write( "15x/15=(71/5)/15
\n" ); document.write( "x=(71/5)(1/15)
\n" ); document.write( "x=71/75
\n" ); document.write( "Check
\n" ); document.write( "6x-2 / 3 + x-3 / 2 = 1/5
\n" ); document.write( "Put the value of x in above equation
\n" ); document.write( "[6(71/75)-2]/3+[(71/75)-3]/2=1/5
\n" ); document.write( "[(426/75)-2]/3+[(71/75)-3]/2=1/5
\n" ); document.write( "[(426-150)/75]/3+[(71-225)/75]/2=1/5
\n" ); document.write( " [(276/75)/3]-[(154)/75]/2=1/5
\n" ); document.write( "(276/75)*(1/3)-(154/75)*(1/2)=1/5
\n" ); document.write( "(92/75)-(77/75)=1/5
\n" ); document.write( "(92-77)/75=1/5
\n" ); document.write( "15/75=1/5
\n" ); document.write( "1/5=1/5\r
\n" ); document.write( "\n" ); document.write( "Explanation on canceling out /3 and /2
\n" ); document.write( "6(6x-2 / 3) + 6(x-3 / 2) =6(1/5)
\n" ); document.write( "we can write above expression as follows
\n" ); document.write( "or [6(6x-2)/3]+[6(x-3)/2]=6/5
\n" ); document.write( "or [6/3(6x-2)]+[6/2(x-3]=6/5
\n" ); document.write( "or 2(6x-2) + 3(x-3) = 6/5\r
\n" ); document.write( "\n" ); document.write( "I hope it clarifies
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