document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480535>Question 480535</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second side of a triangle is 3 more meters than the first side. The third side is twice more than the first side. If the perimeter of the triangle is 47 meters, find the length of the second side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329076 by </B><A HREF=/tutors/aboutme.mpl?userid=mathstutor494><B>mathstutor494(120)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathstutor494><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathstutor494><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329076\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first side be triangle be x<BR>\n" );
document.write( "Then second side of a triangle = x+3<BR>\n" );
document.write( "and accordingly third side = 2x\r<BR>\n" );
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document.write( "Perimeter of the triangle = sum of all the sides = 47<BR>\n" );
document.write( "x+x+3+2x = 47<BR>\n" );
document.write( "4x+3 = 47\r<BR>\n" );
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document.write( "Subtracting 3 from either side results in..<BR>\n" );
document.write( "4x+3-3 = 47-3<BR>\n" );
document.write( "4x= 44 <BR>\n" );
document.write( "Dividing both sides by 4<BR>\n" );
document.write( "x=11\r<BR>\n" );
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document.write( "So second side of a triangle = x+3 = 11+3\r<BR>\n" );
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document.write( "Ans : 14 meter </SPAN>\n" );
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