document.write( "Question 480523: A circle has a diameter AB wher A is the point (6,4) and B is the point (-2,2). Find the radius of th circle and the equation of the circle in general form \n" ); document.write( "

Algebra.Com's Answer #329064 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "A circle has a diameter AB wher A is the point (6,4) and B is the point (-2,2)
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document.write( " (6,4)
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document.write( " (-2,2  
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document.write( "diameter length = sqrt(8^2 + 2^2) = sqrt(68) |D = 
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document.write( "  r = 1/2sqr5t(68) = sqrt(17) 
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document.write( "Standard Form of an Equation of a Circle is 
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document.write( "where Pt(h,k) is the center and r is the radius
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document.write( " (6,4)
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document.write( " (-2,2  C = (2, 3) Midpoint Pt(x,y):  ( , )
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