document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480464>Question 480464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain fish requires 3 hours to swim 15 kilometers downstream. The return trip upstream take 5 hours. Find the speed of the fish in still water. How fast is the current of the stream? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329044 by </B><A HREF=/tutors/aboutme.mpl?userid=Aswathy><B>Aswathy(23)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Aswathy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x and y be the speed of fish in still water and water current respectively.<BR>\n" );
document.write( "Then the speed of fish <BR>\n" );
document.write( "(1)when it swims downstream,<BR>\n" );
document.write( "x+y=15/3=5 (v=s/t)<BR>\n" );
document.write( "(2)when it swims upstream,<BR>\n" );
document.write( "x-y=15/5=3<BR>\n" );
document.write( " so by solving the above pair of linear equation we get x=4 & y=1.<BR>\n" );
document.write( "So, the speed of the fish in still water is 4km/h & the speed of the current is 1km/h. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );