document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480454>Question 480454</A>: <I><SPAN STYLE=\"word-break: break-all;\"> eric is ten years younger than leslie. in ten years, he will be ten years more than one-half  as old as leslie. find their present age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329040 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> eric is ten years younger than leslie. in ten years, he will be ten years more than one-half  as old as leslie. find their present age.<BR>\n" );
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document.write( "Let L = Leslie's present age<BR>\n" );
document.write( "Then Eric's age = L - 10<BR>\n" );
document.write( "In 10 years Leslie's age will be L + 10 and Eric's age will be (L-10) + 10 = L<BR>\n" );
document.write( "Since in 10 years Eric will be 10 more then 1/2 of Leslie, we can write<BR>\n" );
document.write( "L = 1/2(L+10) + 10 <BR>\n" );
document.write( "Solve for L:<BR>\n" );
document.write( "L = L/2 + 15<BR>\n" );
document.write( "L = 30<BR>\n" );
document.write( "Leslie's age = 30<BR>\n" );
document.write( "Eric's age = 20<BR>\n" );
document.write( " </SPAN>\n" );
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