document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480267>Question 480267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On the problem Log (base 1/2)|6x-9|= Log (base 1/2)|-6| , what Logarithm rules do I use? And how do I got about implementing them into this problem to get the answer? I don't even know where to start lol, Thanks in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329029 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329029\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Log (base 1/2)|6x-9|= Log (base 1/2)|-6|<BR>\n" );
document.write( "**<BR>\n" );
document.write( "Since the bases are the same the numbers must also equal to each other, that is:<BR>\n" );
document.write( "|6x-9|=|-6|<BR>\n" );
document.write( "|6x-9|=6<BR>\n" );
document.write( "solving for two conditions<BR>\n" );
document.write( "6x-9=6<BR>\n" );
document.write( "6x=15<BR>\n" );
document.write( "x=15/6=5/2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "-(6x-9=6<BR>\n" );
document.write( "-6x+9=6<BR>\n" );
document.write( "6x=9-6=3<BR>\n" );
document.write( "x=3/6=1/2<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "x=5/2<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x=1/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );