document.write( "Question 49544: tutors, help me please!!!!!thanks
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document.write( "2. Eight years ago, Melanie was twice as old as Roger is now. The sum of their present ages is no more than 41. At most, how old is Roger now? \n" );
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Algebra.Com's Answer #32897 by gsmani_iyer(201)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " Let Reger's age now = x \n" ); document.write( " \n" ); document.write( " So Melanie's age 8 yrs. ago = 2x ....... (given) \n" ); document.write( " \n" ); document.write( " Melanie's present age = 2x+8 \n" ); document.write( " \n" ); document.write( " the sum of their present age = x+2x+8 =< 41 \n" ); document.write( " \n" ); document.write( " So Let us take 41 as the sum now. \n" ); document.write( " \n" ); document.write( " 3x+8 = 41. so 3x = 41-8 = 33 \n" ); document.write( " \n" ); document.write( " x = 11. \n" ); document.write( " \n" ); document.write( " So Roger's present age is = 11. Answer. \n" ); document.write( " |