document.write( "Question 49547: Dearest tutors, can you help me regarding my problem? thank you for that..
\n" ); document.write( "3. How much pure alcohol must be added to 8 quarts of a 20% solution of alcohol produce a 40% solution? \n" ); document.write( "
Algebra.Com's Answer #32896 by AnlytcPhil(1806)\"\" \"About 
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Dearest tutors, can you help me regarding my problem? thank you for that..\r\n" );
document.write( "3. How much pure alcohol must be added to 8 quarts of a 20% solution of alcohol\r\n" );
document.write( "produce a 40% solution?\r\n" );
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document.write( "Let the answer be x.\r\n" );
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document.write( "First we figure the amount of LIQUID we'll have. Then we figure the amount of\r\n" );
document.write( "ALCOHOL we'll have.\r\n" );
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document.write( "We have 8 quarts of LIQUID to start with and we add x quarts of LIQUID, so we\r\n" );
document.write( "end up with 8+x quarts of LIQUID.  \r\n" );
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document.write( "Now we figure the amount of ALCOHOL.\r\n" );
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document.write( "Only 20% of the 8 quarts we start with is ALCOHOL. 20% of 8 quarts is 1.6\r\n" );
document.write( "quarts.  So we have 1.6 quarts of ALCOHOL to start with, and we add x quarts\r\n" );
document.write( "of ALCOHOL, so we end up with 1.6+x quarts of ALCOHOL.\r\n" );
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document.write( "Now we reason that the 1.6+x quarts of ALCOHOL we end up with must be 40%\r\n" );
document.write( "of the 8+x quarts of LIQUID we end up with, so we put that into an equation:\r\n" );
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document.write( "   1.6+x quarts of ALCOHOL EQUALS 40% of 8+x quarts of LIQUID, or\r\n" );
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document.write( "               1.6+x = .40(8+x)\r\n" );
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document.write( "solve that and you'll get x = 8/3 or 2 2/3 quarts.  If you can't solve that,\r\n" );
document.write( "post again and we'll help you solve it.\r\n" );
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document.write( "Edwin
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