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solve Absolute value of 2x-3 is less than or equal to 8x+1
\n" ); document.write( "**
\n" ); document.write( "|2x-3|≤8x+1
\n" ); document.write( "first condition
\n" ); document.write( "2x-3≤8x+1
\n" ); document.write( "-6x≤4
\n" ); document.write( "divide by -6 and switch inequality sign
\n" ); document.write( "x≥-4/6=-2/3
\n" ); document.write( "x≥-2/3 (reject, does not check)
\n" ); document.write( "second condition
\n" ); document.write( "-(2x-3)≤8x+1
\n" ); document.write( "divide by -1 and switch inequality sign
\n" ); document.write( "2x-3≥-8x-1
\n" ); document.write( "10x≥2
\n" ); document.write( "x≥2/10=1/5
\n" ); document.write( "x≥1/5
\n" ); document.write( "..
\n" ); document.write( "solution:
\n" ); document.write( "x≥1/5 \n" ); document.write( "