document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480173>Question 480173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have 1/3 I need to know how many to make 1 gallon? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328876 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328876\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x is the required amount to add in 1/3 to make 1 gallon<BR>\n" );
document.write( "1/3+x=1<BR>\n" );
document.write( "subtract 1/3 both sides of the equation<BR>\n" );
document.write( "(1/3-1/3)+x=1-1/3<BR>\n" );
document.write( "x=1-1/3<BR>\n" );
document.write( "taking LCM on right side<BR>\n" );
document.write( "x=(3-1)/3<BR>\n" );
document.write( "x=2/3 gallon\r<BR>\n" );
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document.write( "So we need to add 2/3 gallon to 1/3 gallon to make 1 gallon.\r<BR>\n" );
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document.write( "Check\r<BR>\n" );
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document.write( "(1/3)+(2/3)=1<BR>\n" );
document.write( "Taking LCM on left side\r<BR>\n" );
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document.write( "(1+2)/3=1<BR>\n" );
document.write( "3/3=1<BR>\n" );
document.write( "1=1\r<BR>\n" );
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document.write( "You have 1/3 gallon </SPAN>\n" );
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