document.write( "Question 480082: Divide and check\r
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document.write( "(x^3+2x^2-3x+2)/(x+1) \n" );
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Algebra.Com's Answer #328857 by stanbon(75887) ![]() You can put this solution on YOUR website! Divide and check \n" ); document.write( "(x^3+2x^2-3x+2)/(x+1) \n" ); document.write( "--- \n" ); document.write( "Using synthetic division: \n" ); document.write( "-1)....1....2....-3....2 \n" ); document.write( "........1....1....-4..|..6 \n" ); document.write( "-----------------------------\r \n" ); document.write( "\n" ); document.write( "Quotient: x^2+x-4 \n" ); document.write( "Remainder: 6\r \n" ); document.write( "\n" ); document.write( "----- \n" ); document.write( "Checking: \n" ); document.write( "(x+1)(x^2+x-4) \n" ); document.write( "= x^3+x^2-4x+x^2+x-4 \n" ); document.write( "= x^3+2x^2-3x-4 + 6 \n" ); document.write( "= x^3+2x^2-3x+2 \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |