document.write( "Question 480082: Divide and check\r
\n" ); document.write( "\n" ); document.write( "(x^3+2x^2-3x+2)/(x+1)
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Algebra.Com's Answer #328857 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Divide and check
\n" ); document.write( "(x^3+2x^2-3x+2)/(x+1)
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\n" ); document.write( "Using synthetic division:
\n" ); document.write( "-1)....1....2....-3....2
\n" ); document.write( "........1....1....-4..|..6
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\n" ); document.write( "\n" ); document.write( "Quotient: x^2+x-4
\n" ); document.write( "Remainder: 6\r
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\n" ); document.write( "Checking:
\n" ); document.write( "(x+1)(x^2+x-4)
\n" ); document.write( "= x^3+x^2-4x+x^2+x-4
\n" ); document.write( "= x^3+2x^2-3x-4 + 6
\n" ); document.write( "= x^3+2x^2-3x+2
\n" ); document.write( "=============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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