document.write( "Question 480083: i^102
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Algebra.Com's Answer #328850 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
Just remember:
\n" ); document.write( "i^1 = i
\n" ); document.write( "i^2 = -1
\n" ); document.write( "i^3 = -i
\n" ); document.write( "i^4 = 1
\n" ); document.write( "then it repeats...
\n" ); document.write( "so, 102/4 is 25 with a remainder of 2 (2nd case from the above set)
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\n" ); document.write( "therefore,
\n" ); document.write( "i^102 = -1
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