document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479955>Question 479955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Michael is thinking of two 2-digits numbers X and Y. X and Y shares the same two digits and the ratio of X to Y is 4/7. She halves the value of X and reduced the value of Y to 1/3 its original value. Next, she subtracts 3 from Y. Both X and Y has the same value now. What was the original numbers X and Y? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328829 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Michael is thinking of two 2-digits numbers X and Y. X and Y shares the same two digits and the ratio of X to Y is 4/7. She halves the value of X and reduced the value of Y to 1/3 its original value. Next, she subtracts 3 from Y. Both X and Y has the same value now. What was the original numbers X and Y?<BR>\n" );
document.write( "be <BR>\n" );
document.write( "Let X be 10t+u <BR>\n" );
document.write( "Y= 10u+t\r<BR>\n" );
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document.write( "(10t+u)/(10u+t)=4/7\r<BR>\n" );
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document.write( "7(10t+u)=4(10u+t)<BR>\n" );
document.write( "70t+7u=40u+4t<BR>\n" );
document.write( "66t-33u=0<BR>\n" );
document.write( "2t-u=0..............1\r<BR>\n" );
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document.write( "1/2(10t+u)   =  ((10u+t)-3)/3<BR>\n" );
document.write( "3(10t+u)=2((10u+t)-3)<BR>\n" );
document.write( "30t+3u=20u+2t-6<BR>\n" );
document.write( "32t-17u=-6...................2\r<BR>\n" );
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document.write( "but u =2t<BR>\n" );
document.write( "substitute u in (2)<BR>\n" );
document.write( "32t-17*2t=-6<BR>\n" );
document.write( "32t-34t=-6<BR>\n" );
document.write( "-2t=-6<BR>\n" );
document.write( "/-2<BR>\n" );
document.write( "t=3<BR>\n" );
document.write( "Therefore u=6\r<BR>\n" );
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document.write( "The numbers are 36 & 63<BR>\n" );
document.write( "CHECK\r<BR>\n" );
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document.write( "36/63 = 4/7\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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