document.write( "Question 479998: 6kg of tea and 11kg of sugar cost 13.30
\n" ); document.write( "11kg of tea and 6kg of sugar cost 17.30
\n" ); document.write( "find the cost of tea and sugar per kilo \n" ); document.write( "
Algebra.Com's Answer #328820 by mananth(16946)\"\" \"About 
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sugar cost x/kg
\n" ); document.write( "Tea cost y/kg\r
\n" ); document.write( "\n" ); document.write( "11x+6y=13.30.......1
\n" ); document.write( "6x+11y=17.30....2\r
\n" ); document.write( "\n" ); document.write( "11 x + 6 y = 13.3 .............1
\n" ); document.write( "6 x + 11 y = 17.3 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -11
\n" ); document.write( "Multiply (2) by 6
\n" ); document.write( "-121 x -66 y = -146.3
\n" ); document.write( "36 x + 66 y = 103.8
\n" ); document.write( "Add the two equations
\n" ); document.write( "-85 x = -42.5
\n" ); document.write( "/ -85
\n" ); document.write( "x = 0.50
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "11 x + 6 y = 13.3
\n" ); document.write( "5.5 + 6 y = 13.3
\n" ); document.write( " 6 y = 13.3 -5.5
\n" ); document.write( " 6 y = 7.8
\n" ); document.write( " y = 1.30 \r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
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