document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479999>Question 479999</A>: <I><SPAN STYLE=\"word-break: break-all;\"> good pm!!\r<BR>\n" );
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document.write( "\"A retail has two kinds of tea,one priced at 15 php per pound and the other at 17 php per pound. How many pounds of the 15 php should the merchant mix with 200 pounds of the 17 php per pound to produce a mixture to sell at 15.80 php per pound?\"\r<BR>\n" );
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document.write( "TNX!:D </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328819 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -------	Price	----------------	quantity										<BR>\n" );
document.write( "Tea type I	17	----------------			200	lb							<BR>\n" );
document.write( "Tea type II	15	----------------			x	lb							<BR>\n" );
document.write( "Total	15.8	----------------	200	+	x	lb							<BR>\n" );
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document.write( "17*200+15*x=15.8(200+x)<BR>\n" );
document.write( "3400+15x=3160+15.8x					<BR>\n" );
document.write( "15x-15.8x=3160-3400					<BR>\n" );
document.write( "-0.8	x	=	-240							/		-0.8											<BR>\n" );
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document.write( "x	=		300	lb	Php 15	Tea type II						<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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