document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479902>Question 479902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Robert left on a trip, traveling at 45 mi/h. One- half hour later, Laura discovered that Robert forgot his luggage, and so she left along the same route, traveling at 54 mi/h, to catch up with him. When did Laura catch up with Robert? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328818 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Robert	45	kmph						<BR>\n" );
document.write( "Laura	54	kmph						<BR>\n" );
document.write( "Difference in time=		01:30=>	1.5	hours				<BR>\n" );
document.write( "Robert	will have covered	67.5	miles	before 	Laura 	starts	from home<BR>\n" );
document.write( "catch up distance=		67.5	miles					<BR>\n" );
document.write( "catch up speed =		54	-45	mph				<BR>\n" );
document.write( "catch up speed =		9	mph					<BR>\n" );
document.write( "Catchup time = catchup distance/catch up speed								<BR>\n" );
document.write( "catch up time=		67.5	/	9				<BR>\n" );
document.write( "catch up time=		7.5	hours					\r<BR>\n" );
document.write( "\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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