document.write( "Question 479725: Please help me find all solutions of the equation in the interval [0, 2pi)
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document.write( "2 sin^2x + 3 sinx + 1 = 0 \n" );
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Algebra.Com's Answer #328795 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Please help me find all solutions of the equation in the interval [0, 2pi) \n" ); document.write( "2 sin^2x + 3 sinx + 1 = 0 \n" ); document.write( "** \n" ); document.write( "let u=sin x \n" ); document.write( "u^2=sin^2 x \n" ); document.write( "2u^2+3u+1=0 \n" ); document.write( "(2u+1)(u+1)=0 \n" ); document.write( "2u+1=0 \n" ); document.write( "u=-1/2 \n" ); document.write( "or \n" ); document.write( "u+1=0 \n" ); document.write( "u=-1 \n" ); document.write( ".. \n" ); document.write( "sin x=u=-1 \n" ); document.write( "x=π \n" ); document.write( ".. \n" ); document.write( "sin x=-1/2 \n" ); document.write( "x=7π/6 and 11π/6 (In quadrants III and IV where sin is negative) \n" ); document.write( "solutions: \n" ); document.write( "x=π, 7π/6, 11π/6 \n" ); document.write( " |