document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479949>Question 479949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the sum of the first fourteen terms of the geometric series 1/3 + 1/12 + 1/49 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328788 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the sum of the first fourteen terms of the geometric series 1/3 + 1/12 + 1/49<BR>\n" );
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document.write( "a = 1/3<BR>\n" );
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document.write( "r = (1/12)/(1/3) = 1/4<BR>\n" );
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document.write( "S(n) = a[1-r^n]/[1-r]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "S(14) = (1/3)[1-(1/4)^14]/[1-(1/4] = (1/3)[1/(3/4)] = (1/3)(4/3) = 4/9<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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