document.write( "Question 479906: The clark family went sailing, their boat averaged 6 kilometers per hour, The Rourke family took their boat out for the same amount of time and their boat averaged 14 K perhour the Rourke family traveled 20 kilometers farther than the Clark family, How many hour did each family spend on their boat trip?
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document.write( "I am trying to figure this one out..I suppose it would be sovling for time right? please let me know thank you so much
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document.write( "maryellen \n" );
document.write( "
Algebra.Com's Answer #328768 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The clark family went sailing, their boat averaged 6 kilometers per hour, \n" ); document.write( "The Rourke family took their boat out for the same amount of time and their boat averaged 14 K perhour \n" ); document.write( " the Rourke family traveled 20 kilometers farther than the Clark family, \n" ); document.write( "How many hour did each family spend on their boat trip? \n" ); document.write( ": \n" ); document.write( "Let t = time they were both on the water \n" ); document.write( ": \n" ); document.write( "Write a dist equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "R's dist - C's dist = 20 km \n" ); document.write( "14t - 6t = 20 \n" ); document.write( "8t = 20 \n" ); document.write( "t = \n" ); document.write( "t = 2.5 hrs the time they were both on the water \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that adds up \n" ); document.write( "2.5(14) - 2.5(6) = \n" ); document.write( "35 - 15 = 20 km difference \n" ); document.write( " |