document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479919>Question 479919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i have 19 coins that are worth $1.10. if they consist only of dimes and nikels, then how many nikels do i have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328764 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the dimes, and let y be the nickels.\r<BR>\n" );
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document.write( "Then you know 1) x+y = 19 since there are 19 coins<BR>\n" );
document.write( "and 2) the value of nickels times the number of nickels plus the value of a dime times the number of dimes should add up to 1.10, which is a fancy way of saying 0.10x+0.05y = 1.10\r<BR>\n" );
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document.write( "So with the two equations, you should be able to solve x and y\r<BR>\n" );
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document.write( "If you cannot do this, reply to me via email and I will give you the full solution </SPAN>\n" );
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