document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49490>Question 49490</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist traveled at a rate of 24 mph to visit a nearby town. The <BR>\n" );
document.write( "cyclist averaged 18 mph on the return trip. if the round trip took 4.9 <BR>\n" );
document.write( "hours, find the distance to the nearby town. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32876 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32876\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> DISTANCE=RATE*TIME OR TIME=DISTANCE/RATE SO THE TIME FOR THE 2 TRIPS \r<BR>\n" );
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document.write( "D/24+D/18=4.9 HOURS OR (18D+24D)/24*18=4.9 OR 42D/432=4.9 OR 42D=432*4.9 OR\r<BR>\n" );
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document.write( "42D=2116.8 OR D=2116.8/42 OR D=50.4 MILES TO THE NEARBY TOWN\r<BR>\n" );
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