document.write( "Question 479772: Can you please put this equation into the standard form of a conic, step-by-step?\r
\n" ); document.write( "\n" ); document.write( "3y^2 + 20x = 23 + 5x^2 + 12y
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Algebra.Com's Answer #328729 by ccs2011(207)\"\" \"About 
You can put this solution on YOUR website!
Step 1: Move all variables to left side and constants to right side
\n" ); document.write( "\"%283y%5E2-12y%29+%2B+%28-5x%5E2%2B20x%29=+23\"
\n" ); document.write( "Use completing the square with both x and y expressions.
\n" ); document.write( "Step 2: factor out leading coefficients:
\n" ); document.write( "\"3%28y%5E2-4y%29+-5%28x%5E2-4x%29+=23\"
\n" ); document.write( "Step 3: Take 2nd coefficient, Halve it, then square it
\n" ); document.write( "\"3%28y%5E2-4y%2B4%29-5%28x%5E2-4x%2B4%29+=+23\"
\n" ); document.write( "Step 4: Multiply leading coefficient by number found in step 3 and add to right side.
\n" ); document.write( "\"3%28y%5E2-4y%2B4%29-5%28x%5E2-4x%2B4%29+=+23%2B12-20+=+15\"
\n" ); document.write( "Step 5: Factor expressions, notice they are perfect squares
\n" ); document.write( "\"3%28y-2%29%5E2+-5%28x-2%29%5E2+=+15\"
\n" ); document.write( "Step 6: Divide equation by 15, In standard form the right side must be 1.
\n" ); document.write( "\"%28%28y-2%29%5E2%29%2F5+-+%28%28x-2%29%5E2%29%2F3+=+1\"
\n" ); document.write( "Now it is in standard form: A vertical Hyperbola with center (2,2)
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